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The class template std::future provides a mechanism to access the result of asynchronous operations When i'm managing some async An asynchronous operation (created via std::async, std::packaged_task, or std::promise) can provide a std::future object to the creator of that asynchronous operation

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The creator of the asynchronous operation can then use a variety of methods to query, wait for, or extract a value from the std. Obviously, they have different methods and stuff, but what is the actual use case Checks if the future refers to a shared state

Returned by std::promise::get_future (), std::packaged_task::get_future () or std::async ()) until the first time get () or share () is called.

The get member function waits (by calling wait ()) until the shared state is ready, then retrieves the value stored in the shared state (if any) Right after calling this function, valid () is false. Int64 if i understand the warning correctly, the object dtype is downcast to int64 Perhaps pandas wants me to do this explicitly, but i don't see how i could downcast a string to a numerical type before the replacement happens.

Unlike std::future, which is only moveable (so only one instance can refer to any particular asynchronous result), std::shared_future is copyable and multiple shared future objects may refer to the same shared state Access to the same shared state from multiple threads is safe if each thread does it through its own copy of a shared_future object. If the future is the result of a call to std::async that used lazy evaluation, this function returns immediately without waiting This function may block for longer than timeout_duration due to scheduling or resource contention delays

The standard recommends that a steady clock is used to measure the duration.

Unpin + future + ?sized, boxed futures only implement the future trait when the future inside the box implements unpin Since your function doesn't guarantee that the returned future implements unpin, your return value will be considered to not implement future You'll not able to await it because your type is basically not a future. In this case it does work

In general, it probably doesn't I'm wondering how this break in backwards compatibility should in general be navigated Perhaps installing a previous version of cmake is the only way that always works That would mean that each project in the future should specify the cmake version on which it should be built.

Wait_until waits for a result to become available

It blocks until specified timeout_time has been reached or the result becomes available, whichever comes first The return value indicates why wait_until returned If the future is the result of a call to async that used lazy evaluation, this function returns immediately without waiting The behavior is undefined if valid () is false before.

I'm confusing myself with difference between a std::future and a std::promise